Jumat, 27 Juli 2012

Analisis Struktur Lewis


Electron valensi H=1 dan O=6

Jumlah pasangan e- valensi = 4 pasang

Pasangan electron berikatan = 2 pasang

Pasangan electron bebas = 4 – 2 = 2 pasang

Pada struktur lewis :

Jumlah pasangan electron pada atom pusat = 4 pasang

Jumlah pasangan electron berikatan = 2 pasang

Jumlah pasangan electron bebas = 2 pasang

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